Important
things to remember!!
__Converting from polar to rectangular:__
**1) x = r cos **~~0~~
**2) y = r sin **~~0~~
__Converting from rectangular to polar:__
** **_{3) r}2_{ = x}2_{ +
y}2
**4) tan **~~0~~ = (y/x)
Click for polar graphing calculator! (Manipula Math)

__Example problems__
**1) Change (3, 4) to polar coordinates.**

__Solution:__ Using property 3 from above,
find r. 3^{2} + 4^{2} = 25 and take the square
root.

**
Therefore, r = 5**

**Using property 4 from above, tan **~~0~~
= (4/3). Use your calculator set to degree mode, the answer is: 53.1 degrees.
(rounded to nearest tenth.

**
**__Therefore, the point is ( 5, 53.1__^{o})

**2) Change ( 4, 150**^{o}) to rectangular coordinates

__Solution:__ Using property 1 from above
x = 4 cos 150. Using your calculator you get x = -3.46 rounded to hundredths.

**Using property 2 from above y = 4 sin 150. Using your
calculator you get y = 2**

**
**__Therefore, the point is ( -3.46, 2)__

**3) Change (-3, -7) to polar coordinates**

__Solution:__ Using property 3 from above
find r. Square -3 and add to the square of -7 you get 58 and taking the
square root on your calculator means r = 7.6 Piece
of cake!

**To find theta we use property 4, tan **~~0~~
= 7/3. Notice I used positive values! I did this to find the reference
angle in quad I. The reference angle is equal to 66.8 degrees. Since we
are in quadrant III, (look at the signs of the original problem) we should
add 180. Why? ( we are in quad III and we memorized we add 180 in that
quad, right?) So the angle is 246.8^{o}.

**
**__Therefore, the point is (7.6, 246.8__^{o}) (
all to simple!!!)
*Note*
**You can use the special functions
on the TI-82 to find all the above answers. Make sure your calculator
is set in degree mode(if you want the answer in degrees) and press 2nd
function angle. This takes you to a menu that has choice 5 and 6
to change to polar form. Choice 5 gives you the radius and choice
6 gives you the theta value. Example (1,3) Get to choice 5 on your
calculator: You should see this **__R arrow Pr__ ( you type 1, 3) and
the calculator gives you 3.16227766. This is r. Round it and your
all set. Then go back to the angle menu and choose 6. You should
see __R arrow P__~~0~~ type 1,3) again and get 71.56505118
round this and the point would be __( 3.2, 71.6__^{o})

** (Yikes
stripes this easy!!)**

**Do basically the same thing
to find x and y by using choices 7 and 8. If the problem is in degrees
set calc to degrees and if in rads make sure calc is in rads.**

__Sketching graphs in polar form using the
TI-82__
Graphs are sketched at the
bottom of the page!
**To use your graphing calculator is extremely easy to graph
in polar form. First, get to the mode screen. Make sure you
highlight the **__radian__ button and drop down one line and highlight
the __pol __button. Now hit the y= key. Instead of y= it's
now r= !! Amazing what modern technology will do!! When you
hit the x, t, theta button, it now shows a theta!! Double
wowie!

__Try a few problems__

**1) r = 3 sin**~~ 0~~ Go ahead, type it
in and hit __graph__. Did you get something that sort of looked
like a circle? Hit __zoom__ then choice __5__. Look better?
It should be a circle tangent at the origin and translated up. The
top point is (0, 3)

**2) r = 4 cos**~~ 0~~ Try this one.
Hit __y=__ and type it in. Hit__ graph.__ This time,
you should get a circle tangent again to the origin but moved to the right.
The point farthest right is (2, 0). Wonder if this is a pattern?
Sine up or down and cosine right or left?

**3) r = - 5 sin **~~0~~
Circle moved down

**4) r = -3 cos**~~ 0~~
Circle moved left.

**5) r = 3 sin 4**~~0 ~~ Interesting
graph. Looks like 8 leaves on a rose. Hit __zoom__
and take choice __1__. Move the cursor to a corner of the picture and
hit __enter__. Hit the down arrow and make the line bigger than
the picture. Hit __enter__ when it is. Now stretch it across
until it makes a box around the picture. Hit __enter__ Now
you see a better picture of it. The number of leaves depend on the
number multiplying ~~0~~. If it is odd that's how many
leaves you get. If it is even like this one, you get double the number
of leaves. Let's see, the number for this problem was 4, I double
it and I should have 8 leaves. Count them on the screen.
How about that. To be a picture like this, the number multiplying
~~0~~ must be bigger than 1 and a whole number.

** 6) r = 4 cos 3**~~0~~
Same as above with 3 leaves.

** 7) r = 3 cos 2**~~0~~
Another leaved rose. This time 4 leaves. Remember after each
problem to reset the calculator to standard zoom by hitting __zoom__
then __6__

** 8) r = 2 + 2 cos**~~ 0~~. A
cardiod. (heart- shaped)

** 9) r = 1 + 2 sin **~~0~~
A limicon

** 10) r = sec **~~0~~
What is this? A vertical line if you remember sec is 1/cos
**Graphs**
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**Let's
head on toward the next section. Geometric representation of complex
numbers!!**
**Sounds
like fun!**